What are the reactants in the chemical reaction CH4 2 O2 CO2 2 H2O?
Oxygen is ALWAYS one of the reactants. Hydrocarbons – compound containing H and C General form: CxHy + O2 → COz + H2O Products are either carbon dioxide or carbon monoxide and water Complete combustion – carbon dioxide and water Ex. CH4 + 2O2 → CO2 + 2H2O Incomplete combustion – carbon monoxide and water.
What type of chemical reaction is CH4 O2 → CO2 H2O?
The reaction is named a combustion reaction. When this reaction takes place, the result is carbon dioxide (CO2), water (H2O), and a great deal of energy. Burning methane releases only carbon dioxide and water.
Why does CH4 O2 CO2 H2O?
Basiclly, the 1/2 O2 is just one oxygen atom out of the two. The double bind is broken, and you get two oxygen ions instead of oxygen gas. 1 molecule of CH4 produces 2 molecules of H2O, so 12 molecules of H2O would require 12/2 = 6 molecules of CH4.
What is reduced in the reaction below CH4 O2 CO2 H2O?
CH4 + 2O2 -> CO2 + 2H20. Is it a redox reaction? In this reaction in the reactant side the carbon is losing hydrogen to form carbon dioxide.So here the carbon is oxidised and also oxygen is gaining hydrogen and getting reduced.
How many grams of H2O are in a mole of CO2?
Therefore, there are 4.125 grams of CO2 produced (= 0.09375 x 44). Fourth, you produce 1 H2O for every O2, or 0.1875 moles of H2O which weighs 3.375 grams (=0.1875 moles x 18 grams/mole). H2O 3.375 grams. Before you say hurray!!!, you can check to make sure the masses balance.
How many moles of O2 are in 6g of CH4?
8 g CH4 / 16 g/mole = 0.50 mole of CH4. 6 g O2 / 32 g/mole = 0.1875 mole of O2. The 0.5 moles of CH4 would normally consume 1.0 moles of O2. We can see , however, that we are going to run out of O2 because there are only 0.1875 moles available. This means that O2 is the limiting reagent.
What happens when CH4 is mixed with O2?
The only problem with this question is that incomplete combustion of CH4 with O2, of which this instance clearly is, results in not only left-over CH4, along with H2O and CO2, but also partial combustion products, mostly CO, and small amounts of CH2O, HCOOH, and CH3OH. The latter three would end up dissolved in the H2O upon condensation.
How do you balance CH4 + 2O2 → CO2 + 2H2O?
Place a coefficient of 2 in front of the O2. We now have 4 O atoms on both sides. CH4 + 2O2 → CO2 + 2H2O The equation is now balanced.