Table of Contents

## How much of a 20\% acid solution would a chemist have to mix with 1 liter of a 40\% acid solution to yield a 36\% acid solution?

250 milliliters

How much of a 20\% acid solution would a chemist have to mix with one liter of a 40\% acid solution to yield a 36\% acid solution? The chemist must add 250 milliliters of the 20\% acid solution.

**How do you solve Percent Solution problems?**

One way to describe the concentration of a solution is by the percent of a solute in the solvent. The percent can further be determined in one of two ways: (1) the ratio of the mass of the solute divided by the mass of the solution or (2) the ratio of the volume of the solute divided by the volume of the solution.

### How many dots are required for 7 rectangles?

a) The number of dots required for 7 rectangles is 52.

**How many pints of 20\% acid solution must be mixed with 70\%?**

We can conclude that 16 pints of 20\% acid solution must be mixed with 24 pints of 70\% solution to obtain 40 pints of 50\% solution. I hope your question was answered. How do you solve mixture problems using system of equations?

#### How many solutions does it take to make 10 liters?

SOLUTION: A chemist has two acid solutions. Solution A contains 10\% acid, and Solution B contains 30\% acid. He will mix the two solutions to make 10 liters of a third solution, Solution C, c.

**How many solutions does a chemist have?**

SOLUTION: A chemist has two acid solutions. Solution A contains 10\% acid, and Solution B contains 30\% acid. He will mix the two solutions to make 10 liters of a third solution, Solution C, c Question 964428: A chemist has two acid solutions.

## How do I prepare solutions through serial dilution?

To prepare solutions through serial dilution, 1 .00 mL of a stock solution is removed using a pipet and added to a 10 mL graduated cylinder. Water is added so that the final volume is 10.00 mL. The solution is mixed and then poured into test tube #2.

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