Why is velocity 0 at maximum height?
Answer: 0 m/s. The instantaneous speed of any projectile at its maximum height is zero. Because gravity provides the same acceleration to the ball on the way up (slowing it down) as on the way down (speeding it up), the time to reach maximum altitude is the same as the time to return to its launch position.
How do you find the time of a projectile?
To define the time of flight equation, we should split the formulas into two cases:
- Launching projectile from the ground (initial height = 0)
- t = 2 * V₀ * sin(α) / g.
- Launching projectile from some height (so initial height > 0)
- t = [V₀ * sin(α) + √((V₀ * sin(α))² + 2 * g * h)] / g.
What happens if a second projectile is launched at 60 degrees?
If a second projectile is launched with the same initial velocity but at an angle of 60 degrees above the horizontal. A ball rolls off the edge of a table. The horizontal component remains constant during its entire trajectory because:
What is the distance traveled by a projectile being affected by gravity?
The equation for the distance traveled by a projectile being affected by gravity is sin(2θ)v 2 /g, where θ is the angle, v is the initial velocity and g is acceleration due to gravity. Assuming that v 2 /g is constant, the greatest distance will be when sin(2θ) is at its maximum, which is when 2θ = 90 degrees.
What is the maximum height a projectile can reach?
Note also that the maximum height depends only on the vertical component of the initial velocity, so that any projectile with a 67.6 m/s initial vertical component of velocity will reach a maximum height of 233 m (neglecting air resistance).
How do you calculate the projectile motion of a projectile?
Our projectile motion calculator follows these steps to find all remaining parameters: Calculate the components of velocity. The horizontal velocity component Vx is equal to V * cos (α). The vertical velocity component Vy is equal to V * sin (α). Three vectors – V, Vx and Vy – form a right triangle.