Why are two numbers which when divided by 6 leave a remainder of 4 and 5 respectively what will be the remainder when Y x is divided by 6?

Why are two numbers which when divided by 6 leave a remainder of 4 and 5 respectively what will be the remainder when Y x is divided by 6?

According to the question, when x is divided by 6 then a remainder of 4 is obtained. Similarly y = 6b + 5 [ where a and b are two positive integers. ] Now by euclids division lemma X²+Y² when divided by 6 leaves a remainder 5. So the answer is 5.

When 5 times a number Y is divided by 8 What is the result of 15?

Answer: your answer is 24.

What is the remainder of 6 divided by 4?

2
The number 6 divided by 4 is 1 with a remainder of 2 (6 / 4 = 1 R. 2). This is also written as 6 /4 = 1.5.

What is the quotient when 15 is divided by 6?

Using a calculator, if you typed in 15 divided by 6, you’d get 2.5.

When the number is divided by 12 the quotient is 15 and the remainder is 10 What is the number?

Step-by-step explanation: x(dividend )=divisor×quotient+remainder x=12×15+10=180+10=190.

How do you write 6 divided by 4?

Explanation: 6 divided by 4 can be written as 6/4 = 3/2.

What are the possible remainders when a number is divided by 7?

If a positive integer is divided by 7, then possible remainders are 1, 2, 3, 4, 5, 6 because if the remainder is 0 or 7 then no. would be divisible by 7.

When divisible by 5 the remainder is 2 What is the remainder when N 2 is divided by 5?

Solution(By Examveda Team) When number ‘n’ is divided by 5 it gives, remainder 2. n^2 /5 ==>Remainder, We can write it in this way, (n*n) /5 ==> Remainder = 2*2 = 4.

What is the remainder when x^3 + y^3 is divided by 6?

Originally Answered: Two numbers, x and y are such that when divided by 6, they leave remainder 4 and 5 respectively. Find the remainder when x^3 + y^3 is divided by 6?

What is the remainder when 599 is divided by 9?

What is the remainder when 599 is divided by 9? The remainder is 5 . To calculate this, first divide 599 by 9 to get the largest multiple of 9 before 599. 5/9 < 1, so carry the 5 to the tens, 59/9 = 6 r 5, so carry the 5 to the digits. 59/9 = 6 r 5 again, so the largest multiple is 66.

How do you find the remainder of 24 divided by 7?

How do I calculate the remainder of 24 divided by 7? Subtract 7 from 24 repeatedly until the result is less than 7. 24 minus 3 times 7 is 3. The number that is left, 3, is the remainder.

What is the remainder when 821 is divided by 4?

There are 3 ways of writing a remainder: with an R, as a fraction, and as a decimal. For example, 821 divided by 4 would be written as 205 R 1 in the first case, 205 1 / 4 in the second, and 205.25 in the third. What is the remainder when 26 is divided by 6?