What would happen to periodic table if there would have been 3 spin quantum numbers?

What would happen to periodic table if there would have been 3 spin quantum numbers?

IF THERE ARE THREE POSSIBLE VALUES FOR SPIN QUANTUM NUMBER, THEN POSSIBLE NUMBER OF ELEMENTS IN THE 5TH PERIOD OF PERIODIC TABLE WOULD BE- s orbitals are 1 in number and p orbitals are 3 in number and d orbitals are 5 in number. If the orbital contain 3 spin quantum number, then totally 27 elements are there.

How many spin quantum numbers are there?

The spin quantum number tells us the orientation of an electron within an orbital and has two possible values: ms = +1/2 for spin up and ms = -1/2 for spin down.

What are quantum numbers on the periodic table?

We use a series of specific numbers, called quantum numbers, to describe the location of an electron in an associated atom. Quantum numbers specify the properties of the atomic orbitals and the electrons in those orbitals. An electron in an atom or ion has four quantum numbers to describe its state.

How many elements would be in the third period of the periodic table if the spin quantum number’s could have the value of 1 1 0 2 2?

Thus, each electron corresponds to 1 element. We can say that if 2 spin quantum numbers are available 8 elements will be present in the third period.

How many elements would be in the second period of the periodic table if the spin quantum numbers could have the value?

And there are 2s and 2p orbitals are in 2nd period which is going to be filled. As given that there are 3 spin quantum numbers(-1/2, 0, +1/2) for each suborbital hence 3 electrons will be there in each suborbital. Thus there will be 3 + 9 = 12 elements in the 2nd period of the periodic table.

What are the only possible values of the spin quantum number in any case?

The three quantum numbers (n, l, and m) that describe an orbital are integers: 0, 1, 2, 3. The principal quantum number (n) cannot be zero. The allowed values of n are therefore 1, 2, 3, 4… The angular quantum number (l) can be any integer between 0 and n – 1.

How are quantum numbers arranged?

The three quantum numbers (n, l, and m) that describe an orbital are integers: 0, 1, 2, 3, and so on. The angular quantum number (l) can be any integer between 0 and n – 1. If n = 3, for example, l can be either 0, 1, or 2. The magnetic quantum number (m) can be any integer between -l and +l.

How many elements are in third period?

eight elements
The third period contains eight elements: sodium, magnesium, aluminium, silicon, phosphorus, sulfur, chlorine, and argon.

How many elements are in 4th period?

18 elements
The fourth period contains 18 elements beginning with potassium and ending with krypton – one element for each of the eighteen groups.

How many spin quantum numbers are there in a D-Block?

Three spin quantum numbers would mean that each orbital can be filled thrice (according to Pauli’s Exclusion Principle). So, the s block would have 3 groups, the d block would have 15 groups and the p block would have 9 groups. So, there would be 27 groups in total.

How many elements in the periodic table can have 3 electrons?

After this hypothetical condition, every orbital can have 3 electron. As in second orbit, 4 orbital are there so total no. of electron is 4×3 = 12. Second period would have 12 elements. Third period would have 12 elements. Periodic table would contain 18×3/2 = 27 groups.

What are the three quantum numbers that describe an orbital?

The three quantum numbers (n, l, and m) that describe an orbital are integers: 0, 1, 2, 3, and so on. The principal quantum number (n) cannot be zero. The allowed values of n are therefore 1, 2, 3, 4, and so on. The angular quantum number (l) can be any integer between 0 and n – 1. If n = 3, for example, l can be either 0, 1, or 2.

What are the rules for the combination of quantum numbers?

Rules Governing the Allowed Combinations of Quantum Numbers. The three quantum numbers ( n, l, and m) that describe an orbital are integers: 0, 1, 2, 3, and so on. The principal quantum number ( n) cannot be zero. The allowed values of n are therefore 1, 2, 3, 4, and so on.