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What will be the output of a 2 inputs NAND gate?
By De Morgan’s laws, a two-input NAND gate’s logic may be expressed as AB=A+B, making a NAND gate equivalent to inverters followed by an OR gate. The NAND gate is significant because any boolean function can be implemented by using a combination of NAND gates. This property is called functional completeness.
What is the minimum number of 2-input NAND gates required to implement a 2-input OR gate?
4
Detailed Solution. The number of 2-input NAND gates required to implement a 2-input XOR gate is 4.
How many 2-input NAND gates are required to implement a 3 input NAND gate?
To realize OR gate using NAND gates, you require 3 NAND gates. Here is an example of a three input AND gate. Notice that the truth table for the three input gate is similar to the truth table for the two input gate. It works on the same principle, this time all three inputs need to be high (1) to get a high output.
When the output of two input OR gate is high?
The output of an XOR gate is HIGH whenever the two inputs are different. The output of an XNOR gate is HIGH whenever the two inputs are identical.
What is the output of 2 input XNOR gate if both the inputs are same?
1
What is the output of 2 Input XNOR gate if both the inputs are same? Explanation: The output of 2 Input XNOR gate is 1 if both the inputs are same. The output of the XNOR gate is 1 if both the inputs are logic 0 or logic 1. This is why they are called as equality detector.
What is the minimum number of 2 input AND gates required to implement the function?
Therefore, the minimum number of 2-input NOR gates needed to implement the function is 3.
How many NAND gates make and gate?
two NAND gates
Using two NAND gates one can make an AND gate.
How many NAND gates are used in an OR gates?
three NAND gates
OR: You need three NAND gates to create an OR gate. First, you use a pair of NAND gates configured as NOT gates to invert the two inputs. Then the third NAND gate produces a LOW output if both of the original inputs are LOW.