Table of Contents
What is the terminal velocity for an egg?
an egg (unprotected). This fundamental force will pull the egg towards certain destruction, unless you can slow its descent or cushion its inevitable impact. In the example above, an egg dropped from 100 m (328 ft) would hit the ground in 4.52 sec, at a final velocity of 44.27 m/sec.
How do you calculate the velocity of a egg drop?
Average velocity is calculated by observing the time in seconds (the x axis) the capsule is released and subtracting it from the time the capsule hits the ground, divided by the drop height.
What is the formula for calculating terminal velocity?
Use the terminal velocity formula, v = the square root of ((2*m*g)/(ρ*A*C)). Plug the following values into that formula to solve for v, terminal velocity. g = the acceleration due to gravity. On Earth this is approximately 9.8 meters per second.
How does velocity affect egg drop?
When an egg is dropped from a higher height, it reaches a greater speed before hitting the ground. So the egg dropped from 5 meters has a greater velocity when it strikes the ground. It thus experiences the greater velocity change during the collision.
How can an egg survive a 100 foot drop?
There are three basic ways to increase the likelihood of safely dropping an egg:
- Slow down the descent speed.
- Cushion the egg so that something other than the egg itself absorbs the impact of landing.
- Orient the egg so that it lands on the strongest part of the shell.
How does terminal velocity affect an egg drop?
When dropped, the egg is accelerated by gravity. When the air resistance (the force experienced when placing one’s hand out in a strong wind), which increases with increasing velocity, equals gravity, the egg’s velocity will remain constant. This velocity is known as terminal velocity.
How do you find the terminal velocity of an experiment?
Measure the diameter of all your marble. Drop the marble gently into the liquid and time how long it takes to fall from X to Y. Measure the length XY and hence determine the terminal velocity of the marble (v). Terminal velocity = Distance (XY)/Time to fall from X to Y.