What is the molarity of a solution that contains 5.0 moles of NaOH in 4.00 l of solvent?
The molarity of the solution is 5.1 mol/L . The solution is said to be 5.1 molar .
What is the molality of a solution that contains 5.0 moles of solute in 2.00 liters of water?
M=5mol2L=2. 5mol/L. 5 m o l / L . Hence, the correct option is A that is 2.5M .
What is the molarity of NaOH in solution prepared by dissolving 4?
The molecular weight of sodium hydroxide is $40g/mol$. The molarity of sodium hydroxide in the solution prepared by dissolving its \[4g\] in water to make a solution of \[250mL\] is $0.4M$.
What is the molarity of a solution containing 5.0 moles of KCL in 5.0 l of solution?
5mol/L. 5 m o l / L . Hence, the correct option is A that is 2.5M .
How do you find the molarity of a solution of NaOH?
To get the molarity, you divide the moles of solute by the litres of solution. “Molarity” = “moles of solute”/”litres of solution” For example, a 0.25 mol/L NaOH solution contains 0.25 mol of sodium hydroxide in every litre of solution.
What is the molality of 10g NaOH in 500g water?
What is the molality of a solution of 10 g NaOH in 500 g water? The molality is 0.50 mol/kg. molality = moles of [solute] (http://socratic.org/chemistry/solutions-and-their-behavior/solute) kilograms of [solvent] (http://socratic.org/chemistry/solutions-and-their-behavior/solvent)
What is 40g of NaOH in 1 litre of solution?
No. of moles of solute= Mass of solute /molar mass. Mass of solute is given as 0.5 g and the molar mass of solute (NaOH) is 23+16+1=40 So, Moles of solute =0.5/40 =0.0125. The molecular weight of NaOH is 40. Therefore, 40g of NaOH in 1 litre of solution is 1N or 1M.
What is the difference between molarity and molar concentration?
So you are not confused with similar chemical terms, keep in mind that molarity means exactly the same as molar concentration (M). Molarity expresses the concentration of a solution. It is defined as the number of moles of a substance or solute, dissolved per liter of solution (not per liter of solvent!).