Table of Contents
- 1 What is the least number which is exactly divisible by 12 and 15?
- 2 What is the smallest 5 digits number which is divisible by 12 15 and 18 A 10010 B 10015 C 10020 D 10080?
- 3 How do you find the least number of five digits that is exactly divisible by 16 18 24 and 30?
- 4 What is the least number which when divided by 12 20 and 24 leaves in each case a remainder of 8?
- 5 How do you find the least 5 digit number?
- 6 What is the least number of 5 digit?
- 7 What is the least common multiple 9 and 4?
- 8 What is the smallest 5 digit number divisible by 6?
- 9 What is the smallest five-digit multiple of 180?
What is the least number which is exactly divisible by 12 and 15?
Required number=LCM of 12,15,20,27=540.
What is the smallest 5 digits number which is divisible by 12 15 and 18 A 10010 B 10015 C 10020 D 10080?
180*56 = 10080. The smallest 5-digit number divisible by 12, 15 and 18 is 10080.
How do you find the least number of five digits that is exactly divisible by 16 18 24 and 30?
Solution : The smallest 5 digit number which is exactly divisible by 16, 18, 24 and 30 is a multiple of the LCM of the given numbers. Therefore, the smallest 5 digit number which is exactly divisible by 16, 18, 24 and 30 is 10080.
What is the least number divisible by 12 15 and 20?
60 is the LCM of 12, 15 and 20.
What is the least number when divided by 6 15 and 18 leave remainder 5 in each case?
Answer: 95 is the least number which when divided by 6, 15, and 18 leaves a remainder of 5 in each case.
What is the least number which when divided by 12 20 and 24 leaves in each case a remainder of 8?
The least number, which when divided by 12, 15, 20 and 54 leaves in each case a remainder of 8 is: [A]. = 548.
How do you find the least 5 digit number?
Least 5 digit number = 10000.
What is the least number of 5 digit?
10,000
The smallest 5-digit number is 10,000 and the greatest 5-digit number is 99,999.
How do you find the least 5 digits?
So the smallest 5 digit number should be the multiple of LCM of 72 and 108 (i.e. 216). Now as we know that the smallest five digit number is 10000. So as we see that the quotient is 46 and remainder is 64. So the number which is exactly divisible by 216 is (10000–64)=9936.
What is the least number when divided by 12 15 20 and 54 leaves 4 as remainder in each case?
∴ Required least such number is 544.
What is the least common multiple 9 and 4?
To find out: The least common multiple (LCM) of the two numbers.
- The prime factor of 4 is 2 and that of 9 is 3.
- Hence, 4 and 9 can be represented as the product of their prime factors as:
- Hence, the least common multiple of 4 and 9 is 36.
What is the smallest 5 digit number divisible by 6?
Find the LCM of the numbers for which we first factorize the numbers as follows: The smallest 5 digit number is 10000. Divide 10000 by 240 to get 41.6666666. Take the next higher integer which is 42. Now multiply 240 by 42 to get 10080, which is the smallest 5 digit number divisible by 6, 8, 15, 16, and 20.
What is the smallest five-digit multiple of 180?
Because smallest 5 digits number is 10000. if we add 80 to it then it will be completely divided by 180 with a quotient 56. LCM (12, 15, 18) = 180. Now, we are to find smallest five-digit multiple of 180. Smallest five-digit number = 10000. (10000 / 180) gives a dividend of 55 leaves a remainder of 100.
What is the least common multiple of 15 20 and 25?
In order for a number to be evenly divisible by 15, 20 and 25 it must be divisible by their least common multiple (LCM). The prime factorizations of the given numbers are 3*5, 2*2*5 and 5*5, respectively. The LCM is 2*2*3*5*5 which equals 300.