What is the last digit of 3 to the 1000th power?

What is the last digit of 3 to the 1000th power?

thus the last digit of 3^1000 will be 1..

What is the last digit of 3 raised to 33?

You know that 3 =(congruent) 3 mod 10 3^2 = 9 mod 10 3^3 = 27 = 7 mod 10 3^4 = 81 = 1 mod 10 so 3^33 = 3^32 * 3 = (3^4)^8 * 3 = 1^8 *3 mod 10 = 3 mod 10 so the last digit of 3^33 is 3.

What are the last two digits of 3 400?

Explanation: Since the last two digits of each term in the binomial expansion is 00 except the first term which has last two digits as 01. So, last two digits of the number 3400 are 01.

What is the last digit of 3 to the power of 100?

100 divided by 4 is exactly 25 or 25 repeats of 3,9,7,1. Therefore the last digits of 3^100 must be 1.

What is the last digit of 5 to the power of 2020?

Answer: the last digit of 5 to the power of 2020 is 25 because 5^6=78125 you will observe that any number will have 25 as the last two digits. And the pattern will repeat till 5^100. Hence the last two digit will be 25.

What is the last digit of 333?

So, when 333 is divided by 4 the remainder is 1, so 373 raised to the power 1 is 373, hence the last digit of the result is 373 raise to the power that is 3.

What is the last two digits of 01 × —21?

Therefore, the last two digits of 51 456 × — 61 567 will be the last two digits of 01 × —21 = 21 Find the last two digits of 19266. 19 266 = (19 2) 133.

How do you find the second last digit of a number?

The trick to finding the second last digit of any number ending with 1 is the UNIT DIGIT of the product of the unit digit of the power and the ten’s digit of the base. It is clear that the unit digit of the given number is 1 and we have to identify the ten’s place digit of the same.

What is the second last digit of 3791 768?

The second last digit always depends on the last two digits of the number so anything before that can be easily neglected. We first convert the number in such a way that the last digit of the base becomes 1. Second last digit of the number will simply be: Eg 1a: Second last digit of 3791 768 = Last digit of 9×8 = 2

How to find the last two digits of 3176 31 76?

Say we need to find the last two digits of 3176 31 76. The trick to finding the second last digit of any number ending with 1 is the UNIT DIGIT of the product of the unit digit of the power and the ten’s digit of the base. It is clear that the unit digit of the given number is 1 and we have to identify the ten’s place digit of the same.