Table of Contents
What is the last digit of 2 raise to 100?
so last digit of 2^100=6.
What is the last digit of 2 to the power 87?
The last digit of 2^87 * 3^43 is 6.
What is the last digit of 7355?
a 3
and the last digit of 7355 is a 3. so that 3 ∣∣28 − 1, 5 ∣∣28 − 1, and 11 ∣∣28 − 1, and since the integers 3, 5, and 11 are pairwise relatively prime, then 165 ∣∣28 − 1 also, that is, 28 ≡ 1 (mod 165).
Which of the following number is divisible by 72?
When we list them out like this it’s easy to see that the numbers which 72 is divisible by are 1, 2, 3, 4, 6, 8, 9, 12, 18, 24, 36, and 72.
What will be the last digit of 73 75?
7
Last digit of 73^75 is 7.
What is the value of 2 Power 72?
| Power | Value |
|---|---|
| 69 | 590,295,810,358,705,651,712 |
| 70 | 1,180,591,620,717,411,303,424 |
| 71 | 2,361,183,241,434,822,606,848 |
| 72 | 4,722,366,482,869,645,213,696 |
What is the value of 2 raise to 100?
Powers of 1024
| 20 | = | 1 |
|---|---|---|
| 290 | = | 1 237 940 039 285 380 274 899 124 224 |
| 2100 | = | 1 267 650 600 228 229 401 496 703 205 376 |
| 2110 | = | 1 298 074 214 633 706 907 132 624 082 305 024 |
| 2120 | = | 1 329 227 995 784 915 872 903 807 060 280 344 576 |
What is the last digit of the powers of two?
The positive powers of two — 2, 4, 8, 16, 32, 64, 128, 256, … — follow an obvious repeating pattern in their ending digit: 2, 4, 8, 6, 2, 4, 8, 6, …. This cycle of four digits continues forever. There are also cycles beyond the last digit — in the last m digits in fact — in the powers of two from 2 m on.
What are the last two digits of 21 72?
Now 33 4 ends in 21 (33 4 = 33 2 × 33 2 = 1089 × 1089 = xxxxx21) therefore, we need to find the last two digits of 21 72. By the previous method, the last two digits of 21 72 = 41 (tens digit = 2 × 2 = 4, unit digit = 1) So here’s the rule for finding the last two digits of numbers ending in 3, 7 and 9:
How to find the last two digits of number raised to power?
How to find the Last Two Digits of Number raised to Power. Let the number be in the form ${x^y}$. Based on the value of units digit in the base i.e x, we have four cases. Case 1: Units digit in x is 1. If x ends in 1, then x raised to y, ends in 1 and its tens digit is obtained by multiplying the tens digit in x with the units digit in y.
What are the last two digits of (79) 142?
Now, units digit of a number ending in 41 to the power of 71 is 1 and its tens digit is obtained by multiplying 4 and 1 which is 4. Hence, the last two digits of ( 79) 142 are 4 and 1. ( 79) 142 ends in 41 (From previous example) and ( 79) 1 ends in 79.