Table of Contents
- 1 What are possible two numbers for which x/y 60?
- 2 What are two positive numbers?
- 3 How do you find the difference between positive and negative numbers?
- 4 How do you find the maxima and minima using Lagrange multipliers?
- 5 What is the minimum and maximum value of P 60x-x^2?
- 6 What is the maximum value of X with x = 20?
What are possible two numbers for which x/y 60?
The two numbers are x and y such that x + y = 60. ∴By second derivative test, x = 15 is a point of local maxima of f. Thus, function xy3 is maximum when x = 15 and y = 60 − 15 = 45. Hence, the required numbers are 15 and 45.
What are two positive numbers?
Positive numbers include the natural, or counting numbers like 1,2,3,4,5, as well as fractions like 3/5 or 232/345, and decimals like 44.3.
How do you write a positive number?
A positive number can be written with a “+” symbol in front of it, or just as a number. For example, the numbers “+3” and “3” stand for the same numbers. In the above line, the positive numbers 1, 2, 3, 4, 5 and 6 are shown.
How do you find the difference between positive and negative numbers?
If the two numbers are on opposite sides of 0 (e.g., −5 and 2), then you add the absolute values (e.g., |−5|+|2|=5+2=7), or alternatively subtract the negative number from the positive one which effects a sign change (e.g., 2−(−5)=2+5=7).
How do you find the maxima and minima using Lagrange multipliers?
1.1 Use Lagrange multipliers to find the maximum and minimum values of the func- tion subject to the given constraint x2 + y2 = 10. We can classify them by simply finding their values when plugging into f(x, y). So the maximum happens at (3, 1) and the minimum happens at (-3, -1).
How do you find two positive real numbers whose sum is 40?
How do you find the two positive real numbers whose sum is 40 and whose product is a maximum? We would like to find where the product x ⋅ y is maximum, but from the above equation we can write: x ⋅ y = x ⋅ (40 −x) = −x2 + 40x.
What is the minimum and maximum value of P 60x-x^2?
First, a correction. If you look at Yash’s answer, you’re correctly supposed to minimize the fn P=60x-x^2. But this is a cap-shaped parabola, whose minimum doesn’t exist. The maximum however does exist , at x=30 , P (30) = 900.
What is the maximum value of X with x = 20?
There is only one such value (critical point) with x = 20. Now the second derivative f ”(x) = − 2 is negative everywhere, and therefore is negative at the critical point x = 20. Hence, x = 20 is a maximum for f. But we also know that y = 40− x, so the value of y is also 20.
How do you find two positive numbers whose sum is 300?
Find two positive numbers whose sum is 300 and whose product is a maximum. Solution Find two positive numbers whose product is 750 and for which the sum of one and 10 times the other is a minimum. Solution Let x x and y y be two positive numbers such that x +2y =50 x + 2 y = 50 and (x+1)(y +2) ( x + 1) ( y + 2) is a maximum.