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How much time does it take for the ball to hit the ground?

Posted on October 23, 2022 by Author

Table of Contents

  • 1 How much time does it take for the ball to hit the ground?
  • 2 How long does it take in seconds for the ball to get back to the platform?
  • 3 What is the acceleration when a ball is thrown vertically upward?
  • 4 How do you calculate the time of flight of a ball?

How much time does it take for the ball to hit the ground?

To decide where the balls land, we need to determine how long the balls are in the air. Both balls will take 2 seconds to hit the ground.

How long does it take in seconds for the ball to get back to the platform?

so t = 48 / 9.81 = 4.89 seconds. Originally Answered: A ball is thrown vertically upwards from the ground with an initial velocity of 50m/s.

At what velocity must a ball be thrown straight up in order for it to reach a maximum height of 30m acceleration due to gravity is 9.8 m/s s?

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0 m/s
Therefore, at maximum altitude the velocity of the ball must be zero. Question: A ball thrown vertically upward reaches a maximum height of 30 meters above the surface of Earth. At its maximum height, the speed of the ball is: Answer: 0 m/s.

What is the initial velocity of the ball at maximum height?

– Physics Q&A A ball is thrown vertically upwards with a velocity of 49 m/s. Calculate (1) The maximum height to which it rises. (2) The total time it takes to return to the surface of the earth. Initial velocity of the ball (u) = 49m/s. The velocity of the ball at maximum height (v) = 0.

What is the acceleration when a ball is thrown vertically upward?

When a ball is thrown vertically upward, it’s acceleration is -g(-9.8m/s) because it’s motion is in opposite direction to the gravitational attraction on the body, it’s velocity, v, at it’s highest point is zero while it’s initial velocity u is given by;

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How do you calculate the time of flight of a ball?

Plugging in the needed values the time of flight = 2 * 30 m/s / 9.8 m/s^2. The quotient is 6.12 seconds. If you drop the ball from the right height it will hit the ground at 30 m/s and so if you throw the ball up at 30 m/s it will stop at the same height. 30 = gt where 30 is the right velocity.

How high would the ball reach if the initial speed becomes 2U?

If a ball thrown vertically upwards with initial speed of “u” reached “h” meters, how high would the ball reach if the initial speed becomes 2u (in terms of h)? If you want quick answer then it is 2h in terms of 2u.

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