How much of a 10 liter 30\% acid solution must be replaced with pure acid to obtain 10 liters of a 50\% solution?

How much of a 10 liter 30\% acid solution must be replaced with pure acid to obtain 10 liters of a 50\% solution?

Answers and Replies 7.143L of 30\%.

How many liters of acid should be added to 60 l of a 25\% acid solution in order to produce a 40\% acid solution?

So, if you add 15 L of pure acid to 25 L of 60\% v/v acid solution, you’ll get 40 L of 75\% v/v acid solution.

How many liters pure acid are there in 8 liters of a 25\% solution?

=1.6L (ans.)

How many mL of 60\% acid should be added to pure acid to make 50ml of 85\% acid?

You need to add 18.75 mL of 60\% solution to pure acid to make 50 mL of 85\% acid.

What quantity of 60\% acid solution must be mixed with a 30\% solution to produce 300 ml of a 50\% solution?

At the end, the amount of acid you want to end up with is 50\% of 300ml, so that’s 150 ml. Since x + y = 300, that means that x = 200. So you will need 200 ml of 60\% solution and 100 ml of 30\% solution.

How many liters of pure acid should be added to 3 liters of water to obtain a 40\% solution?

To obtain 40\% solution the ratio of water to acid has to be 6:4. As we have 3ltrs of water we must have 4(3/6). Ans = 2ltrs of acid.

How many liters of a 90\% acid solution must be added to 6 liters of a 15\% acid solution to obtain a 40\% acid solution?

So, we add 3 L of 90 \% acid to 6 L of 15 \% acid and get 9 L of 40 \% acid .

How many Litres of pure acid are there in 10 Litres of 30 solution of acid?

Therefore 10= (50+ V) x8/100 . So V= 6 x 100/8= 600/8= 75- LITRES.

What amount of pure acid must be added to 300 ml of a 40\% acid solution to produce a 60\% acid solution?

40\% (40/100=0.4) of the solution is 0.4 X (300mL) = 120mL of a liquid acid, and that the 60\% of the original solution that is not acid is 0.6 X (300mL) = 120mL of water. (120mL)/0.3 = 400mL.

How many liters of pure acid must be added to 6 liters of a 15\% acid solution to obtain a 40 acid solution?