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How many ways can 5 couples be seated around a table?

Posted on November 15, 2022 by Author

Table of Contents

  • 1 How many ways can 5 couples be seated around a table?
  • 2 How many ways can five people be seated in a circle?
  • 3 How many seats can a wife sit next to her husband?
  • 4 What is the number of seating arrangements (permutations) of a round table?

How many ways can 5 couples be seated around a table?

Each couple can be seated in two different ways while still remaining next to each other. There are 5 such couples, so there are 2^5=32 ways to arrange the couples, for each of those 24 ways to seat the couples.

How many ways can five people be seated in a circle?

b. The number of three-letter word sequences is 5P3 = 60. c.

How many ways can 5 people sit around a circular table if Alice and Bob won’t sit next to each other?

= 362,880 ways. The number of circular permutations of distinct objects is , because permutations related by a simple rotation are not considered different.

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How many married couples are to be seated at a round table?

Originally Answered: 5 married couples are to be seated at a round table. How many ways can be arrange if everyone must be seated next to their spouse? First, pair each couple together. You have . Now seat the pairs.

How many seats can a wife sit next to her husband?

That leaves 2/5 seats where her husband can sit next to her. Second wife, say, can take any of the four remaining seats. There is then only 1 seat out of the remaining 3 where her husband can sit next to her AND leave two empty adjacent seats for the last couple.

What is the number of seating arrangements (permutations) of a round table?

The first couple has a choice of 10 ways to choose 2 seats adjacent to each other at a round table. The remaining 4 couples are then confined to 4! ways to select 4 pairs of seats. Each couple may then arrange to be seated in 2 ways beside one another. The number of seating arrangements (permutations) is therefore = (10) (4!) (2)^5 = 7680.

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How many couples can be seated in $2^3$ ways?

There are three couples, so each one of them can be seated in $2^3$ ways as couple. Now the three couples are three people and they can be placed in around the circular table in $2!$ ways. Now the required probability $= \\frac{2^3.2}{5!} = \\frac{2}{15}$

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