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How many ways 5 white and 4 black balls be arranged in a row so that no two black balls are together?

Posted on August 31, 2022 by Author

Table of Contents

  • 1 How many ways 5 white and 4 black balls be arranged in a row so that no two black balls are together?
  • 2 What is the probability to draw a white ball from bag A if we know that we drew exactly a total of 2 white balls total?
  • 3 What is the probability of getting white?
  • 4 What is permutation and combination?
  • 5 How many balls can be drawn from a bag?

How many ways 5 white and 4 black balls be arranged in a row so that no two black balls are together?

In 15 ways, 5 white and 4 black balls be arranged in a row so that no two black balls are together.

How many ways can 5 balls be chosen so that 2 are red and 3 are black *?

If you draw five, you HAVE to get at least two black, because there are only three red. There are 3C3 * 5C2 = 10 ways to get three red. Since this is the only way to NOT get three black, there are 56–10 = 46 ways to get at least three black.

What is the probability that at least 4 of the balls are white?

11/243
The probability that at least 4 of the balls drawn are white is. = 11/243.

What is the probability to draw a white ball from bag A if we know that we drew exactly a total of 2 white balls total?

The probability of a white ball in the second pick is 4/7. Total probability of drawing two white balls is 5/8*4/7 (since they are independent events). If you picked a black ball initially, picking another black ball would have a probability of 2/7, on similar grounds , total prob for 2 blacks would be 3/8*2/7.

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How many possible ways are there in drawing 3 balls from the box of 6 balls?

The bag contains 2 White, 3 Black and 4 Red balls. So, total 9 balls are there in the bag; among them 3 are Black and 6 are non-Black balls. Three balls can randomly be drawn in (9C3) = 84 ways. 1 Black and 2 non-Black balls can be drawn in (3C1)*(6C2) = 45 ways.

What is the probability that at least 6 of the balls are white?

1 Expert Answer The probability of selecting at least 6 white balls out of the 8 is 0.10868.

What is the probability of getting white?

Therefore the probability of getting a white ball is 7/20. Therefore the probability of getting a black ball is 1/5.

What is the probability that a number 5 is drawn?

There are four 5s and 12 face cards in a standard 52 card deck, so the probability of getting a face card or a 5 is 16/52 or 4/13. In a deck of 52 cards, we have 4 suits: There are 26 red cards and 26 black cards. In 26 red cards we have 13 cards of Heart suit and 13 of Diamond suit.

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How many ways can 3 balls be selected?

Three balls can randomly be drawn in (9C3) = 84 ways. 1 Black and 2 non-Black balls can be drawn in (3C1)*(6C2) = 45 ways.

What is permutation and combination?

A permutation is an act of arranging the objects or numbers in order. Combinations are the way of selecting the objects or numbers from a group of objects or collection, in such a way that the order of the objects does not matter.

What is the probability that all three balls are white?

1/56
Three balls are drawn from the bag at random. The probability that all the three balls are white, is. = 1/56.

What is the ordering between the three black balls?

The three black balls then get placed between the white balls, or to the side of them. So the first one has 6 spaces to choose from, the second has 5, and the third has 4. 6*5*4=120. This value includes the ordering between the 3 identical black balls, which needs to remove, so we just divide by 120 by 3!=6 (so 120/6=20) to remove that ordering.

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How many balls can be drawn from a bag?

A bag contains 2 white balls, 3 black balls and 4 red balls. In how many ways can 3 balls be drawn from the bag, if at least one black ball is to be included in the draw 64 128 132

How many red and white balls are there in a box?

A box contains 5 different red and 6 different white balls. In how many ways can 6 balls be selected so that there are at least two balls of each color? A box contains 5 different red and 6 different white balls. In how many ways can 6 balls be selected so that there are at least two balls of each color? Was this answer helpful?

How many ways can be drawn in (6C1)*(3c2)?

The bag contains 2 White, 3 Black and 4 Red balls. So, total 9 balls are there in the bag; among them 3 are Black and 6 are non-Black balls. Three balls can randomly be drawn in (9C3) = 84 ways. 1 Black and 2 non-Black balls can be drawn in (3C1)* (6C2) = 45 ways. 1 non-Black and 2 Black balls can be drawn in (6C1)* (3C2) = 18 ways.

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