How many moles of KClO3 are required to produce 22.8 moles oxygen O2?

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How many moles of KClO3 are required to produce 22.8 moles oxygen O2?

You’d need 33.3 moles of potassium chlorate, KClO3 , to produce that much oxygen.

How many moles of O2 are in KClO3?

2- moles of KClO3 on heating produces 3- moles of oxygen gas.

How many moles of KClO3 are required to produce 2.4 moles O2?

2KClO3 – 2KCl + 3O2. calculate the amount of KClo3 required to produce 2.4 mole of oxygen. so using unitary method , x can be calculated as . Therefore 1.6 moles of KClO3 are required to produce 2.4 moles of O2.

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How many moles of oxygen are produced when 20 moles of KClO3 decomposes?

In the decomposition of potassium chlorate, 20 moles of O2 was produced. How many mole of KClO3 decomposed? – Quora. 20 mol O2 * 2 mol KClO3 /3 mol O2 = 13.3 mol KClO3 decomposed.

How many moles of KClO3 are needed to produce 30 6.6 moles of O2?

Therefore, 4 moles of potassium chlorate must be used to produce 6 moles of oxygen gas.

How many moles of O2 are in 2 moles of KClO3?

According to the balanced reaction, the decomposition of two moles of potassium chlorate gives two moles of potassium chloride, and three moles of oxygen.

How many moles of KClO3 are required?

Selina – Chemistry – Class 7 Hence, 4 moles of KClO3 are required to give 6 moles of oxygen.

What is the ratio of KClO3 to O2 in moles?

The ratio between KClO3 and O2 is 2 : 3 This means that the decomposition of 2 moles of KClO3 produces 3 moles of O2 moles O2 that can be obtained from ne mole of KClO3 = 1 x 3 / 2 = 1.5 1 mole of KCLlO3 * (3moles KClO3/2moles O2) = 1.5 moles of O2.

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What is the product of decomposition of KClO3?

Oxygen is prepared by catalytic; decomposition of potassium chlorate (KClO3) . Decomposition, of potassium chlorate gives potassium chloride (KCl) and oxygen (O2) . How many moles and how many grams of KClO3 are required to produce 2.4 mole O2?

How many moles of potassium chlorate are required to produce 6 moles oxygen?

Therefore, 4 moles of potassium chlorate must be used to produce 6 moles of oxygen gas.

How many moles of oxygen gas O2 has been given to you?

So, 6 moles of Oxygen Gas O2 has been given to you. To calculate the number of moles for potassium chlorate KClO3, use the mole ratio. number of moles given to you from compound 1 ÷ the front number for compound 1 × the front number for another compound.