How many moles of carbon dioxide CO2 are produced from the combustion of 1 mole of octane?

Posted on by Author

How many moles of carbon dioxide CO2 are produced from the combustion of 1 mole of octane?

eight moles
Burning one mole of octane (114 grams), therefore, would produce eight moles of CO2, with a weight of 352 grams (8 x 44).

How many moles of CO2 are produced from 16 grams of O2?

One mole of CO2 has mass of 44 g and 32 g of O2. So 16 g of O2 have 22 g of CO2 or 0.5 moles of it. Frm the equation 32g O2 produces 1 mole CO2. Hence 16g O2 produces 16 /32 =1/2 mole Co2.

READ:   Can you get into a PA program with a low GPA?

How many moles of O2 are in a mole of CO2?

1 mole of O2 has a mass of 32g. So (44/32)=1.375 moles of O2 have the same mass as 1 mole of CO2.

How do you find the moles of CO2 in a reaction?

Calculate the number of moles of CO2 by the formula n=PV/RT, where P is the pressure from Step 3, V is the volume from Step 2, T is the temperature from Step 1 and R is a proportionality constant equal to 0.0821 L atm / K mol.

How much does 1 mole of CO2 weigh?

44.01 g/mol
Carbon dioxide/Molar mass

How many grams of CO2 are produced from 5 moles O2?

The mass of carbon dioxide produced (to one significant figure) is 400 g.

What is the mass percentage of O in CO2?

72.7\%
Oxygen has a molar mass of 16.0 g mol−1 , so 1 mole of oxygen atoms has a mass of 16.0 g . Therefore, carbon dioxide has a percent composition of 72.7\% oxygen, i.e. for every 100 g of carbon dioxide you get 72.7 g of oxygen.

READ:   What would cause goodwill to increase?

How many grams of HgO are in 2 moles of O2?

125g O2 1 mol O2 2 mol HgO 32.0 g O2 1 mol O2 = 7.81 mol HgO How many grams of mercury are produced if 24.5 moles of mercury (II) oxide decomposes? 24.5 mol HgO

How many moles are required to completely react with NH3?

not present Find: mol NH3 mol NH3 molar Moles Moles and Chemical Reactions f you have 1.0 mole many will be required to required to completely react all of the

What is the formula for mercury(II) oxide?

169.9g AgNO3 2 mol AgNO3 = 1.03×10-2 mol Cu Mercury (II) oxide decomposes into mercury and oxygen gas. Write and balance the equation. 2HgO → 2Hg + O2

What is the limiting reagent for C3H8 and O2?

Conclusion: for every 3.11 moles of C3H8 you will need 15 moles of O2, but you don’t have that when we look at the original equation. So O2 is the limiting reagent. If you would like more practice, click “Extra Practice”!

READ:   How are samples prepared in IR spectroscopy?