Table of Contents
- 1 How many grams of ammonia would be produced from 50g of nitrogen?
- 2 How many G NO can be produced when 25.0 g of nitrogen reacts?
- 3 How many grams of hydrogen H2 are necessary to react completely with 25.0 g of nitrogen N2?
- 4 How many grams of NH3 are produced if 1-12 moles are used?
- 5 How much nitrogen does it take to make amonia?
How many grams of ammonia would be produced from 50g of nitrogen?
We have 50 g of nitrogen gas here, so we need to find the number of moles of nitrogen. From here, we would produce 1.79⋅2=3.58 moles of ammonia. 3.58mol ⋅17.031 gmol ≈61 g of NH3 .
How many grams of hydrogen are necessary to react completely with 50.0 g of nitrogen gas?
10.7 grams
Therefore, 10.7 grams of Hydrogen are necessary to fully react with 50.0 grams of Nitrogen.
How many G NO can be produced when 25.0 g of nitrogen reacts?
The mass of NO produced from 25.0 g oxygen is 46.9 g. When 25.0 g of nitrogen and 25.0 g of oxygen are reacted, the amount of NO produced will be 46.9 g.
How many grams of hydrogen are necessary to react completely with 50.0 g of nitrogen 3H2 N2 2NH3?
10079 H 3
ng pas del Page 7 Given the balanced equation: N2 + 3H2 → 2NH3 How many grams of hydrogen are necessary to react completely with 50.0 g of nitrogen in the above reaction? 10079 H 3.
How many grams of hydrogen H2 are necessary to react completely with 25.0 g of nitrogen N2?
Since there are 3 significant figures in the question, we will use 3 significant figures and the answer is: 10.8 g hydrogen. Keep in mind the stoichiometry of the equation allows us to react both of the reactants completely. If you don’t follow the balanced equation, you will have an excess of one of the reactants.
How many g NO can be produced when 25.0 g of nitrogen reacts?
How many grams of NH3 are produced if 1-12 moles are used?
The equation MUST be c. Example: 3 + N2 2 Using the same equation, how many grams of NH3 are produced if 10.57 moles of 1-12 are used in a reaction? 10.57 mol (2 mol NH3 17.04 g 3 mol 1-12 Mole to Mole ratio from the BALANCED chemical equation! 1 mol NH3 Mole to gram conversion with the molar mass from the Periodic Table number.
How many grams of H2 are required to produce 10g NH3?
1.776 g H2 is required to produce 10.00 g NH3, if N2 is in excess. Get a free SEO tool from Ahrefs. Monitor your SEO health, backlinks and keywords for free.
How much nitrogen does it take to make amonia?
Nitrogen and hydrogen react together to form amonia: N2 + 3H2 → 2NH3. When completely converted, 7 tonnes of nitrogen gives 8.5 tonnes of ammonia. How much nitrogen will be needed to produce 34 tonnes of amonia? so 28 tonnes of N2 is needed to get 34 tonnes of NH3.
How do you calculate the mass of NH3 from H2?
Multiply 0.58716 mol NH3 by the mole ratio between H2 and NH3 in the balanced equation, so that mol NH3 cancel, leaving mol H2. Calculate the mass of 0.88074 mol H2. m H2 = 0.88074 mol H2 × 2.016 g H2/mol H2 = 1.776 g H2 to four significant figures 1.776 g H2 is required to produce 10.00 g NH3, if N2 is in excess.