Skip to content

ProfoundQa

Idea changes the world

Menu
  • Home
  • Guidelines
  • Popular articles
  • Useful tips
  • Life
  • Users’ questions
  • Blog
  • Contacts
Menu

How do you prove a graph is connected?

Posted on January 9, 2023 by Author

Table of Contents

  • 1 How do you prove a graph is connected?
  • 2 How many cycles does a connected graph G with n vertices and n edges have?
  • 3 How do you prove a simple graph does not exist?
  • 4 How do you determine the order of a graph?
  • 5 How do you prove a graph is a cycle?
  • 6 How do you find the sum of degrees of vertices?

How do you prove a graph is connected?

A graph is said to be connected if every pair of vertices in the graph is connected. This means that there is a path between every pair of vertices. An undirected graph that is not connected is called disconnected.

What is the order of graph G?

The order of a graph G is the cardinality of its vertex set, and the size of a graph is the cardinality of its edge set. Given two vertices u and v, if uv ∈ E, then u and v are said to be adjacent.

How many cycles does a connected graph G with n vertices and n edges have?

one cycle
Show that G has exactly one cycle. Let G have n vertices and n edges. Since G is a connected graph, it has a spanning tree T with n vertices and n − 1 edges.

READ:   Is Nigel a common name in England?

Can you have a simple graph with n vertices with the degrees of vertices 0 1 n − 1 if yes construct such a graph for N 5 If not argue why not?

Since there are n vertices, if they all have different degrees, they must be 0,1,2,…,(n-1). But then we have that the vertex of degree (n-1) must have an edge to all other vertices, and the vertex of degree 0 has no edges. This is a contradiction so no such graph can exist.

How do you prove a simple graph does not exist?

If any of the vertices is connected to vertices, then it is connected to all the vertices except from itself. If this were true, no vertex would be disconnected (being connected with 0 other). Therefore, a graph with vertices with a 0 degree vertex and another of degree cannot exist.

How do you prove that a graph is 2 connected?

A graph is connected if for any two vertices x, y ∈ V (G), there is a path whose endpoints are x and y. A connected graph G is called 2-connected, if for every vertex x ∈ V (G), G − x is connected.

READ:   What does ball mean ammo?

How do you determine the order of a graph?

First order, would be natural log of concentration A versus time. If you get a straight line with a negative slope, then that would be first order. For second order, if you graph the inverse of the concentration A versus time, you get a positive straight line with a positive slope, then you know it’s second order.

How do you determine graph order and size graph?

Order of a graph is the number of vertices in the graph. Size of a graph is the number of edges in the graph.

How do you prove a graph is a cycle?

Proof: Let G be a graph with n vertices. If G is connected then by theorem 3 it is not a tree, so it contains a cycle. If G is not connected, one of its connected components has at least as many edges as vertices so this component is not a tree and must contain a cycle, hence G contains a cycle.

How do you show that a graph is complete?

READ:   How can India increase its exports?

In the graph, a vertex should have edges with all other vertices, then it called a complete graph. In other words, if a vertex is connected to all other vertices in a graph, then it is called a complete graph.

How do you find the sum of degrees of vertices?

The number of edges connected to a single vertex v is the degree of v. Thus, the sum of all the degrees of vertices in the graph equals the total number of incident pairs (v, e) we wanted to count. For the second way of counting the incident pairs, notice that each edge is attached to two vertices.

How many edges can a simple graph G on n have if it is not connected?

Alternate solution There are exactly k(n−k) edges between vertices in the two pieces. If you add them to your graph, you get a simple graph, which by handshaking lemma, has at most n(n−1)2 edges.

Popular

  • Why are there no good bands anymore?
  • Does iPhone have night vision?
  • Is Forex trading on OctaFX legal in India?
  • Can my 13 year old choose to live with me?
  • Is PHP better than Ruby?
  • What Egyptian god is on the dollar bill?
  • How do you summon no AI mobs in Minecraft?
  • Which is better Redux or context API?
  • What grade do you start looking at colleges?
  • How does Cdiscount work?

Pages

  • Contacts
  • Disclaimer
  • Privacy Policy
  • Terms and Conditions
© 2025 ProfoundQa | Powered by Minimalist Blog WordPress Theme
We use cookies on our website to give you the most relevant experience by remembering your preferences and repeat visits. By clicking “Accept All”, you consent to the use of ALL the cookies. However, you may visit "Cookie Settings" to provide a controlled consent.
Cookie SettingsAccept All
Manage consent

Privacy Overview

This website uses cookies to improve your experience while you navigate through the website. Out of these, the cookies that are categorized as necessary are stored on your browser as they are essential for the working of basic functionalities of the website. We also use third-party cookies that help us analyze and understand how you use this website. These cookies will be stored in your browser only with your consent. You also have the option to opt-out of these cookies. But opting out of some of these cookies may affect your browsing experience.
Necessary
Always Enabled
Necessary cookies are absolutely essential for the website to function properly. These cookies ensure basic functionalities and security features of the website, anonymously.
CookieDurationDescription
cookielawinfo-checkbox-analytics11 monthsThis cookie is set by GDPR Cookie Consent plugin. The cookie is used to store the user consent for the cookies in the category "Analytics".
cookielawinfo-checkbox-functional11 monthsThe cookie is set by GDPR cookie consent to record the user consent for the cookies in the category "Functional".
cookielawinfo-checkbox-necessary11 monthsThis cookie is set by GDPR Cookie Consent plugin. The cookies is used to store the user consent for the cookies in the category "Necessary".
cookielawinfo-checkbox-others11 monthsThis cookie is set by GDPR Cookie Consent plugin. The cookie is used to store the user consent for the cookies in the category "Other.
cookielawinfo-checkbox-performance11 monthsThis cookie is set by GDPR Cookie Consent plugin. The cookie is used to store the user consent for the cookies in the category "Performance".
viewed_cookie_policy11 monthsThe cookie is set by the GDPR Cookie Consent plugin and is used to store whether or not user has consented to the use of cookies. It does not store any personal data.
Functional
Functional cookies help to perform certain functionalities like sharing the content of the website on social media platforms, collect feedbacks, and other third-party features.
Performance
Performance cookies are used to understand and analyze the key performance indexes of the website which helps in delivering a better user experience for the visitors.
Analytics
Analytical cookies are used to understand how visitors interact with the website. These cookies help provide information on metrics the number of visitors, bounce rate, traffic source, etc.
Advertisement
Advertisement cookies are used to provide visitors with relevant ads and marketing campaigns. These cookies track visitors across websites and collect information to provide customized ads.
Others
Other uncategorized cookies are those that are being analyzed and have not been classified into a category as yet.
SAVE & ACCEPT