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How do you find the probability of at least three?

Posted on September 2, 2022 by Author

Table of Contents

  • 1 How do you find the probability of at least three?
  • 2 What is the probability that at least two students share a birthday?
  • 3 How many ways can two people have the same birthday?
  • 4 How many possible combinations of birthdays are there in a group?

How do you find the probability of at least three?

The probability of at least three wins can be expressed as: 1 – P(exactly 0 wins) – P(exactly 1 win) – P(exactly 2 wins). So, to solve this, you just need to know how to calculate P(exactly k wins).

What is the probability of at least one 3?

The probability of rolling at least one 3 is 1–25/36=11/36, a bit less than 1/3.

What is the probability that at least two students share a birthday?

In a room of just 23 people there’s a 50-50 chance of at least two people having the same birthday. In a room of 75 there’s a 99.9\% chance of at least two people matching.

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What is the probability that at least two people have the same birthday?

The number of ways that all n people can have different birthdays is then 365 × 364 ×⋯× (365 − n + 1), so that the probability that at least two have the same birthday is Numerical evaluation shows, rather surprisingly, that for n = 23 the probability that at least two people have the same birthday is about 0.5 (half the time).

How many ways can two people have the same birthday?

The number of ways that all n people can have different birthdays is then 365 × 364 ×⋯× (365 − n + 1), so that the probability that at least two have the same birthday is.

How many people in a room can have the same birthday?

23 people. In a room of just 23 people there’s a 50-50 chance of at least two people having the same birthday. In a room of 75 there’s a 99.9\% chance of at least two people matching.

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How many possible combinations of birthdays are there in a group?

If one assumes for simplicity that a year contains 365 days and that each day is equally likely to be the birthday of a randomly selected person, then in a group of n people there are 365 n possible combinations of birthdays. The simplest solution is to determine the probability of no matching birthdays and then subtract this probability from 1.

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