How do you find the last two digits of a factorial?

How do you find the last two digits of a factorial?

In this case we consider the leading two non zero digit upto 30 and manually we multiply the last two digits of the remaining 2 terms with the result. The generalized formula to find the last two non zero digits of N = × 12 [ N / 5 ] × Last two digits of the remaining terms.

How do you find the digits of a factorial?

Factorial of a number is calculated by multiplying the digits in a number while decrementing the value of digit by 1. It is denoted by the symbol ‘! ‘ i.e. 0!, 1!, 2!, 3!, 5!,….,etc. Factorial of 0! and 1! is always 1.

What are the last two digits of 7 to the power 2008?

Find the last two digits of 72008 (CAT 2008) So, the last two digits are 01.

How do you find the last number?

To find last digit of a number, we use modulo operator \%. When modulo divided by 10 returns its last digit. To finding first digit of a number is little expensive than last digit. To find first digit of a number we divide the given number by 10 until number is greater than 10.

How to find the last two digits of \\:\\31^{76}}\\)?

Say we need to find the last two digits of \\({31^{76}}\\). The trick to finding the second last digit of any number ending with 1 is the UNIT DIGIT of the product of the unit digit of the power and the ten’s digit of the base. It is clear that the unit digit of the given number is 1 and we have to identify the ten’s place digit of the same.

What are the last two digits of (17) 256?

Hence, the last two digits of ( 17) 256 are 8 and 1. If x ends in 2, 4, 6, 0r 8, we can find the last two digits of the number raised to power with the help of the following points : Here, 2 raised to 10 ends in 24 and 24 raised 105, which is an odd number, ends in 24.

What are the last two digits of (79) 142?

Now, units digit of a number ending in 41 to the power of 71 is 1 and its tens digit is obtained by multiplying 4 and 1 which is 4. Hence, the last two digits of ( 79) 142 are 4 and 1. ( 79) 142 ends in 41 (From previous example) and ( 79) 1 ends in 79.

What are the last two digits of 31 786?

The last digit of the first term is 1. So the last two digits of 31 786 are 81. Now, here is the shortcut: Here are some more examples: In no time at all you can calculate the answer to be 61 (4 × — 9 = 36). Therefore, 6 will be the tens digit and one will be the units digit) Now try to get the answer to this question within 10 s: