How do you find how many grams of excess reactant are left over?

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How do you find how many grams of excess reactant are left over?

To find the amount of remaining excess reactant, subtract the mass of excess reagent consumed from the total mass of excess reagent given.

How many grams of AlCl3 will be produced if 2.50 moles of Al react?

Answer to Question #162269 in General Chemistry for ian. How many grams of AlCl3 will be produced if 2.50 moles of Al react? The coefficients before Al and AlCl3 are equal, so from 2.50 moles of Al 2.50 moles of AlCl3 are obtained. m(AlCl3)=2.50*133.5=333.75(g).

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How many moles of Al2O3 are formed when 0.78 moles of O2 reacts with Aluminium?

2 mole of Al2O3. 3 mole of O2 reacts with 4 mole of aluminium to give =2 mole of Al2O3. Hence 0.78 mole of oygen react with Aluminium to give 0.52 mole of Al2O3.

How do you calculate moles produced?

Determine the moles of product produced by dividing the grams of product by the grams per mole of product. You now have calculated the number of moles of every compound used in this reaction.

How many moles of NO2 will be produced from 7 moles of O2?

7 mol of NO2 will be produced. According to the equation 7mol*7/4 = 12. 25 mol of O2 reacts.

How many moles of AlCl3 will produced?

Solving these equations, we see that, beginning with 6.0 grams of aluminum, 0.22 moles of AlCl3 can be formed, and that, beginning with 3.8 grams of chlorine, 0.036 moles of AlCl3 can be formed.

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How many moles of oxygen are in Al2O3?

1 mole Al2O3 contains 2 moles of Al and 3 moles of O. Weight of one mole of oxygen is 16 g and Al is 27 g. So moles of O are 3 and Al are 2.

What is the mole ratio of Al2O3 O2?

As per the equation , 2 moles of Aluminum Oxide ( Al2O3 ) produces 4 moles of Aluminum ( Al ) and 3 moles of Oxygen ( O2 ).

How many moles of Al2O3 are formed when aluminum reacts with oxygen?

When 6.38 moles of O2 and 9.15 moles of Al react, the ratio of aluminum to oxygen is 9.15/6.38 = 1.434. This shows that all of the oxygen is consumed before the aluminum and when the reaction ends the reactant aluminum is left. The number of moles of Al2O3 formed is approximately 4.25 moles.

What is the ratio of aluminum to oxygen in 4Al+3O2?

4Al + 3O2 –> 2Al2O3 3 moles of O2 react with 4 moles of Al to give 2 moles of Al2O3. The ratio of the number of moles of aluminum to the number of moles of oxygen required in the reaction should be 4/3. When 6.38 moles of O2 and 9.15 moles of Al react, the ratio of aluminum to oxygen is 9.15/6.38 = 1.434.

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How many moles of oxygen are needed to completely react with ammonia?

Conversion Factors from Eqns How many moles of oxygen are needed to completely react with 2.34 moles of ammonia in a reaction that yields nitrogen monoxide and water? 4 NH 3+ 5 O 2→ 4 NO + 6 H

How do you find the number of moles in a reaction?

Determine the moles of product produced by dividing the grams of product by the grams per mole of product. You now have calculated the number of moles of every compound used in this reaction. 41.304 g of NaCl ÷ 58.243 g/mol = 0.70917 moles of NaCl.