Table of Contents
How do you check if a number is divisible by 5 in Matlab?
\% [x] = div5(x) – to checks a real number if it is divisible by 5.
How do you determine if it is divisible of 5 and 10?
The Rule for 10: Numbers that are divisible by 10 need to be even and divisible by 5, because the prime factors of 10 are 5 and 2. Basically, this means that for a number to be divisible by 10, the last digit must be a 0.
How do you check whether a number is divisible by 5 and 11 or not?
To check divisibility with 5 and 11 both, check if((num \% 5 == 0) && (num \% 11 == 0)) , then number is divisible by both 5 and 11.
What is the number divisible by 5 and 12?
60
Therefore, 60 is the number which is divided by 5 and 12. Therefore, the number 60 is divisible by both 5 and 12 always.
How do you write divisible in Matlab?
Direct link to this answer
- function [Res] = divisible(n)
- if(rem(n,3)==0 && rem(n,5) == 0)
- Res = 1;
- else.
- Res = 0;
- end.
What Is REM in Matlab?
r = rem( a , b ) returns the remainder after division of a by b , where a is the dividend and b is the divisor. This function is often called the remainder operation, which can be expressed as r = a – b.
What is the divisible by 5 and 10?
The numbers 567860 and 55650, have 0 in ones place. Hence, they are divisible by both 5 and 10.
What is the divisibility rules of 10?
In order to apply the divisibility rule for 10, the digit that is last in a number has to be 0. This works whether the number is 70, 700, or 7,000. The rule also works if the numbers do not have 0 as a middle digit such as 210, 340, and 620. All of them are divisible by 10.
How do we know if a number is divisible by 5?
Divisibility by 5 is easily determined by checking the last digit in the number (475), and seeing if it is either 0 or 5. If the last number is either 0 or 5, the entire number is divisible by 5. If the last digit in the number is 0, then the result will be the remaining digits multiplied by 2.
What is the divisibility of 12?
Divisibility rules for numbers 1–30
| Divisor | Divisibility condition |
|---|---|
| 12 | It is divisible by 3 and by 4. |
| Subtract the last digit from twice the rest. The result must be divisible by 12. | |
| 13 | Form the alternating sum of blocks of three from right to left. The result must be divisible by 13. |