Table of Contents
- 1 How do we determine the Planck constant?
- 2 How does Photoekctric effect determine Planck’s constant?
- 3 How do you find the Planck’s constant from stopping potential and wavelength?
- 4 How do you calculate Planck’s constant from stopping voltage?
- 5 How do you calculate stopping potential in photoelectric effect?
- 6 How do you calculate stopping voltage in photoelectric effect?
How do we determine the Planck constant?
The value for Planck’s constant is the slope of your graph multiplied by e/c where e is the electronic charge (1.6022 x 10-19 C) and c is the velocity of light (2.998 x 108 m/s).
How does Photoekctric effect determine Planck’s constant?
- 12 – 1. EXPERIMENT 12. THE PHOTOELECTRIC EFFECT AND PLANCK’S CONSTANT.
- = (3)
- Whf. eV.
- (6) The form of (6) is the same as that of a straight line, y = mx + b, where the ordinate is the stopping potential V,, the abscissa is frequency f , the slope is (eh/ ), and the intercept is e Wf / .
Which filters are used in laboratory for determination of Planck’s constant?
For determination of Planck’s Constant and work function: 1. Insert the red color filter (635nm), set light intensity switch (12) at strong light, voltage direction switch (16) at ‘-‘, display mode switch (10) at current display.
How do you find the Planck’s constant from stopping potential and wavelength?
Planck’s constant can be found through the equation: E = h * frequency = KE(max) + Wo which can be rewritten in the form V(stopping) = h/e * f + Wo/e , the equation of a line with slope equal to h/e. Multiplying by the value for e, one may calculate the value of h, Planck’s constant.
How do you calculate Planck’s constant from stopping voltage?
What is the formula for stopping potential?
Given: Stopping potential = Vs = 2 V, wavelength of incident light = λ = 2000 Å = 2000 x 10-10 m, speed of light = c = 3 x 108 m/s, Planck’s constant = h = 6.63 x 10-34 Js, Charge on electron = e = 1.6 x 10-19 C.
How do you calculate stopping potential in photoelectric effect?
In order to make it across the gap, the initial KE of the ejected electron must be greater than the PE at the collector. When the voltage equals the stopping potential, we know that the KE fo the ejected electrons just equals the potential energy at the collector or… KE = PE hf – φ = qV. This equation is very useful.
How do you calculate stopping voltage in photoelectric effect?
To Find: Stopping potential = Vs =? Given: Initial frequency = ν1 = 2.2 x 1015 Hz, initial stopping potential = Vs1 =6.6 V, Final frequency = ν2 = 4.6 x 1015 Hz, Final stopping potential = Vs2 = 16.5 V, Charge on electron = e = 1.6 x 10-19 C.