Table of Contents
- 1 How many ways are there to distribute six indistinguishable objects into four indistinguishable boxes so that each of the boxes contains at least one object?
- 2 How many ways are there to distribute 5 distinguishable balls into 4 distinguishable boxes so that no box is empty?
- 3 How many ways are there to distribute 6 objects into 5 boxes?
- 4 How many ways are there to distribute six objects to five boxes?
- 5 How many ways are there to distribute six indistinguishable balls into nine distinguishable bins?
- 6 How can we determine the distinguishable object?
How many ways are there to distribute six indistinguishable objects into four indistinguishable boxes so that each of the boxes contains at least one object?
=(64)⋅3=45 possibilities.
How many ways are there to distribute 5 distinguishable balls into 4 distinguishable boxes so that no box is empty?
=24, for a total of 240. Your first part is correct.
How many ways are there to distribute 12 distinguishable objects into six distinguishable boxes so that two objects are placed in each box?
ways. 10,395 is the number of ways to place2 each of 12 distinguishable balls in 6 indistinguishable bins, So 10,395×6! =7,484,400, the desired answer.
How many ways are there to place 10 indistinguishable balls into 8 distinguishable bins?
19,448 ways
Example: How many ways are there to place 10 indistinguishable balls into 8 distinguishable bins? Solution: We have C(10 + 8 – 1, 10) = C(17, 10) = 19,448 ways to arrange 10 indistinguishable balls into 8 distinguishable bins.
How many ways are there to distribute 6 objects into 5 boxes?
1 Approved Answer So, the total number of ways to place 5 distinct objects in 6 distinct boxes is 6*6*6*6*6 = 6^5 = 7776 Hence, there are 7776 ways to place five objects in six boxes when both are labeled.
How many ways are there to distribute six objects to five boxes?
▶ How many ways are there to distribute 5 cards to each of 4 players from a deck of 52 cards? ▶ How many ways are there to place 10 indistinguishable balls into 8 distinguishable bins? ▶ How many ways to distribute six distinguishable objects to five distinguishable boxes?
How many ways are there to put 4 distinguishable balls into 3 distinguishable boxes?
14 ways
Example 1 – How many ways are there to put four different balls into three indistinguishable offices without exclusion? This gives us a total of- 1 + 3 + 4 + 6 = 14 ways.
How many ways are there to distribute 6 indistinguishable balls into nine?
evaluating the number of ways to distribute six indistinguishable balls into nine distinguishable bins, we can use the combination formula. This is because order is not important and repetition is allowed. The combination formula is C(n+r−1,r). =14!/6!(
How many ways are there to distribute six indistinguishable balls into nine distinguishable bins?
How can we determine the distinguishable object?
To find the number of distinguishable permutations, take the total number of letters factorial divide by the frequency of each letter factorial. Basically, the little n’s are the frequencies of each different (distinguishable) letter. Big N is the total number of letters.
How many ways are there to place 8 indistinguishable balls in 4 distinguishable bins?
How many ways are there to place 8 indistinguishable balls into 4 distinguishable bins? = 11!/(8!
How many ways to distribute 5 balls into 3 boxes if each box must have at least one ball in it if?
We have to distribute 5 distinct balls into 3 identical boxes. Thus, n = 5 and k = 3. Therefore, there are a total of 41 possibilities.