Table of Contents
- 1 How many numbers greater than 4000 can be made by using the digits 2 3 4 and 5 repetition of the numbers?
- 2 How many even numbers can be formed using the digits 2 3 4 5 6?
- 3 How many numbers greater than 400000 can be filled with 6 digits?
- 4 How many numbers can you count from the number 4?
- 5 How many numbers are there in 4×6?
How many numbers greater than 4000 can be made by using the digits 2 3 4 and 5 repetition of the numbers?
While digit 4, 5, and 6 can take this place. Now, we have the remaining 4 numbers and the remaining three digits can be taken by any of them to form a number greater than 4000. Hence, the number of numbers that are greater than 4000 which can be formed using the digits 2, 3, 4, 5, 6 without repetition is 192.
How many even numbers can be formed using the digits 2 3 4 5 6?
Final Conclusion: The number of 3-digit even numbers that can be formed using given digits, with repetition allowed, is 168.
How many five digit even numbers greater than 40000 can be made using?
The five-digit number must start either with 4 or with 5. So, two options are available for the ten thousand’s digit. For each option, the remaining four digits can be filled in (5^4) ways. Therefore, if repetition of digits are allowed, there are {2 * (5^4)} = 1250 ‘five-digit numbers’ which all are larger than 40000.
How many numbers greater than 400000 can be filled with 6 digits?
There are 6 digits and the numbers greater than 400000 will have 6 digits. We have to use all 6 digits at a time, the numbers greater than 400000 will have either 4 or 5 at the extreme left position. 1. When 5 is at the extreme left position, the remaining 5 places can be filled with the digits 0,2,2,4,4. This can be done in 2!2!5!
How many numbers can you count from the number 4?
You have a problem that breaks down fairly easily. The first digit has to be either a 4, a 5, or a 6. Every number you could make starting with the number 4 will be greater than 40,000, so you can count them all.
How many digits are left to permute with 5 numbers?
From there you have 5 digits to re-arrange, but the permutation would have to end in an even number. Starting with 5 you would end with either 4, 6 or 0; Thus you would have 4 digits left to permute and 3 even numbers to end with so: (4!) (3)
How many numbers are there in 4×6?
The numbers will range from 42356 to 65432. The first digit must be 4, 5, or 6. The last digit must be 2, 4, or 6. If the first digit is 4 or 6, there will only be two choices for the last digit. There will be 6 possible arrangements for the middle three digits. So far that is 4 x 6 = 24 numbers.