Table of Contents
- 1 How many ways can 5 boys and 5 girls be seated at round table of 3 particular girls must not sit together?
- 2 How many ways May 5 students be seated in a row of 5 chairs for a pictorial?
- 3 How many ways can 2 boys and 3 girls be seated in a circular position?
- 4 How many ways can 5 boys and 5 girls be seated?
- 5 How do you assign seats between two girls in a circle?
- 6 How many ways can 3 girls occupy in $6_{\\mathbf p_3}$ways?
How many ways can 5 boys and 5 girls be seated at round table of 3 particular girls must not sit together?
Thus, (n-1)! = (8-1)! = 7! = 5, 040 Moreover, the 3 girls can be arranged within its group in (3) (2) (1) = 6ways.
How many ways May 5 students be seated in a row of 5 chairs for a pictorial?
Of ways the can be seated=5×4×3×2×1=120. So, 5 people can be seated in 5 seats in 120 ways.
How many ways can 2 boys and 3 girls be seated in a circular position?
possible arrangements
Answer and Explanation: (a) The total number of ways in which 2 boys and 3 girls can be arranged: 5! =120. possible arrangements.
How many ways can 4 boys and 3 girls be arranged in a row such that no two girls stand next to each other?
In how many ways can 4 girls and 3 boys sit in a row such that just the girls are to sit next to each other? Answer: 288.
How many ways to seat 3 girls on a round table?
Third: According to the requirement of the assignment, that means the two closest girls sitting must have space. Therefore, after placing 5 boys on the round table, there are still 5 gaps between the 5 boys. Putting 3 girls into 5 gaps means we have P 5 3 ways to seat 3 girls
How many ways can 5 boys and 5 girls be seated?
The total of ways for seating these 5 boys and 5 girls with he constraint of having 3 particular girls, randomly chosen from among 5 girls, to sit together = 10* (3!) (7!) = 302,400. How many ways can 5 boys and 5 girls be seated at a round table if 3 particular girls must not sit together?
How do you assign seats between two girls in a circle?
Pick a start and number the seats 1 to 8 around the circle. The number of seats between two consecutive girls cannot cannot be two for all three pairs and cannot be one for all three pairs. So, without loss of generality, we can assign seats 1, 3, and either 5 or 6 for the girls.
How many ways can 3 girls occupy in $6_{\\mathbf p_3}$ways?
The blank spaces are the places where 3 girls can be allotted. So in 6 spaces 3 girls can occupy in $6_{\\mathbf P_3}$ways and 5 boys will interchange between themselves in $5!$ways. So total number of ways is $5!×6_{\\mathbf P_3}= 14400$