How many ways can 10 chairs be divided and arranged for 2 cabins A and B with 4 and 6 chairs respectively?

How many ways can 10 chairs be divided and arranged for 2 cabins A and B with 4 and 6 chairs respectively?

In how many ways can 10 objects be split into two groups containing 4 and 6 objects, respectively? – Quora. You can pick the first group of 4 from the 10 objects in 10C4 ways, or 210 ways. That leaves the 6 objects for the second group. Or, you can pick the 6 objects for the first group in 10C6 ways, or 210 ways.

How many ways can 4 people sit in 10 chairs?

So there is 5040 ways to pick 4 people from a starting pool of 10. You have 4 chairs with 4 people that can sit in them. Each time you pick a person to sit down, it reduces how many for the next pick by one.

How many different ways can 10 students be seated in a row of 10 chairs?

Ten ( 10 ) STUDENTS may be seated in a row 10! ways. This is because each student can be seated in any of the 10 seats. So, there could be 3628800 possible arrangements.

How many ways can 7 boys seat around circle?

Complete step-by-step answer: Since in this question we have to arrange persons in a circle and 7 persons have to be arranged in a circle so that every person shall not have the same neighbor. Hence there are 360 ways to do the above arrangement and therefore the correct option is A.

How many ways can 10 chairs?

By stars and bars we have (5+3−15−1)=(74) number of ways to do so. Multiplying by the number of ways to arrange the persons themselves among the seats labeled P we have a total of 4! (74)= 7P4=840 arrangements, same as the other answer. You have 10 chairs, 4 individuals.

What are the no of ways of seating 7 candidates?

3c3 is the answer. 105.

How many ways can 4 people sit in 12 chairs?

I broke the question down into 2 parts, then solved them and multiplied the answer to get 11,880 ways.

How many ways can 10 students line up?

10! = 10 · 9 · 8 · 7 · 6 · 5 · 4 · 3 · 2 · 1 = 3,628,800 .

How many ways can a person sit in a 12-person table?

For each combination of 4 chairs selected out of the 12, there are different ways the people can sit in them – we can have persons A B C D, or A B D C, etc. There are, in fact 4! ways each selection of chairs can be sat in.

How many ways can 3 men be seated in 3 seats?

Now that we’ve done this, the 3 men can be seated in the remaining seats in 3! or 6 ways. Note that we haven’t used the formula for circular arrangements now. This is because after the women are seated, shifting the each of the men by 2 seats will give a different arrangement.

How many ways do the chosen two people not sit next to each other?

The total number of ways the chosen two people do not sit next to each other is 10! − 9 ⋅ 2 ⋅ 8! = 2, 903, 040. Thanks for contributing an answer to Mathematics Stack Exchange!

How many ways can C and D be seated together?

Similar to (i) above, the number of cases in which C and D are seated together, will be 12. Therefore the required number of ways will be 24 – 12 or 12. Example 3 In how many ways can 3 men and 3 women be seated at around table such that no two men sit together?