Table of Contents
- 1 How many liters of a 30 salt solution must be added to 6 liters of an 80\% salt solution to obtain a 50\% salt solution?
- 2 How much salt must be added to 60 kg of a 20\% solution of salt to increase it to a 40\% solution of salt?
- 3 What quantity of water should be added to reduce 16 Litres of 25\% acidic liquid to 20\% acidic liquid?
- 4 What quantity of water should be added to reduce?
- 5 What quantity of water should be added to reduce 6 Litres?
How many liters of a 30 salt solution must be added to 6 liters of an 80\% salt solution to obtain a 50\% salt solution?
1 Expert Answer Let X be the number of liters of salt solution needed.
How much salt must be added to 60 kg of a 20\% solution of salt to increase it to a 40\% solution of salt?
for short trick:required salt=60*(40-20)/(100-40)=20kg. for being 40\% the ratio would be (12+x)/(60+x)=40/100 where x is the required amount on solving the aove equation we get x=20kg.
How many liters of water must be added to 8 liters of a 40 acid solution?
24 liters
Therefore, 24 liters of water must be added to 8 liters of a 40\% acid solution to obtain a 10\% acid solution.
How much acid should be added to 200ml of 10\% solution to strengthen it to one of 20\% acid solution?
R D Sharma – Mathematics 9 x ml acid add to 10 percent of 200 ml solution is equal to 20 percent of acid solution. After solving. x =25 ml.
What quantity of water should be added to reduce 16 Litres of 25\% acidic liquid to 20\% acidic liquid?
If you have 16 liters of 25\% acidic water, then this implies that we have 16(0.25)= 4L of acid. We want to know how much water we need to add to the existing 16L to obtain a solution that is 20\% acid. So we must add 4 more liters of water.
What quantity of water should be added to reduce?
Answer: The quantity of water required = 1.8 liters. Step-by-step explanation: Given : Water should be added to reduce 6 liters of 50\% acidic to 20\% acidic water.
How much acid should be added to 400 ml of 15\% acid solution to increase its strength to 32 \%?
3 Answers By Expert Tutors Let x ml of acid be add to this solution. x = 100 ml of acid. therefore 160ml – 60ml = 100 ml is the amount needed acid to be added.
How much pure alcohol should be added to 600 ml of a 15\% solution to make its strength 32\%?
Therefore, 100 mL of alcohol should be added to make the strength 32\%. This is the required answer.
What quantity of water should be added to reduce 6 Litres?
Answer: The quantity of water required = 1.8 liters.