What is the integration of √ 1 sin2x?

What is the integration of √ 1 sin2x?

or (1-sin2x)^1/2=(cosx-sinx) =(sinx-cosx). I= sinx+cos x +C . ,Answer. I= -cosx – sinx+ C , Answer.

How do u integrate sin2x?

Answer: ∫sin2x dx = −½ cos(2x)+C.

What is the anti derivative of sin2x?

Answer: The antiderivative of sin2 x is x/ 2 – (sinx cosx) / 2.

What is sin2A and 2sinA?

2sinA means that 2 times the value of sin A. However, it’s totally different from sin 2A. Sin 2A Means that the value of x is doubled that is sin of two times x.

What is integral integration in calculus?

Integration is an important tool in calculus that can give an antiderivative or represent area under a curve. The indefinite integral of f (x) f ( x), denoted ∫ f (x)dx ∫ f ( x) d x , is defined to be the antiderivative of f (x) f ( x).

How does Wolfram|Alpha do integrals?

Wolfram|Alpha computes integrals differently than people. It calls Mathematica’s Integrate function, which represents a huge amount of mathematical and computational research. Integrate does not do integrals the way people do. Instead, it uses powerful, general algorithms that often involve very sophisticated math.

What is the definite integral of f(x)?

The definite integral of f (x) f (x) from x = a x = a to x = b x = b, denoted ∫b a f (x)dx ∫ a b f (x) d x, is defined to be the signed area between f (x) f (x) and the x x axis, from x= a x = a to x= b x = b. Both types of integrals are tied together by the fundamental theorem of calculus.

How do you find the derivative of an indefinite integral?

Since the derivative of a constant is 0, indefinite integrals are defined only up to an arbitrary constant. For example,∫ sin(x)dx= −cos(x)+constant ∫ s i n ( x) d x = − c o s ( x) + c o n s t a n t, since the derivative of −cos(x)+constant − c o s ( x) + c o n s t a n t is sin(x) s i n ( x).